TS EAMCET · Maths · Three Dimensional Geometry
If \(L\) is the line of intersection of two planes \(x+2 y+2 z=15\) and \(x-y+z=4\) and the direction ratios of the line \(L\) are \((a, b, c)\), then \(\frac{a^2+b^2+c^2}{b^2}=\)
- A 14
- B 10
- C 22
- D 26
Answer & Solution
Correct Answer
(D) 26
Step-by-step Solution
Detailed explanation
Intersection line of planes \(x+2 y+2 z=15\) and \(x-y+z=4\) is \(\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 1 & 2 & 2 \\ 1 & -1 & 1\end{array}\right|=4 \hat{i}+\hat{j}-3 \hat{k}\) So, \(\frac{a^2+b^2+c^2}{b^2}=\frac{16+1+9}{1}=26\)
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