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TS EAMCET · Maths · Complex Number

If \(1, \omega, \omega^2, \ldots \omega^8\) are the roots of the equation \(x^9-1=0\), then \(\sum_{r=1}^s\left(\omega^r\right)^{99}=\)

  1. A \(0\)
  2. B \(8\)
  3. C \(1\)
  4. D \(\omega\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(8\)

Step-by-step Solution

Detailed explanation

It is given that \(1, \omega, \omega^2, \ldots, \omega^8\) are the roots of equation \(x^9-1=0\). So, sum of roots \(=0\) \(\Rightarrow 1+\omega+\omega^2+\ldots+\omega^8=0\) and \(\omega^9=1\) Now,…
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