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TS EAMCET · Maths · Straight Lines

A line segment joining a point A on \(x\)-axis to a point B on \(y\)-axis is such that \(\mathrm{AB}=15\). If P is a point on AB such that \(\frac{\mathrm{AP}}{\mathrm{PB}}=\frac{2}{3}\) then the locus of P is

  1. A \(x=9 \cos \theta, y=6 \sin \theta\)
  2. B \(x=6 \cos \theta, y=9 \sin \theta\)
  3. C \(x=6 \cos \theta, y=6 \sin \theta\)
  4. D \(x=9 \cos \theta, y=9 \sin \theta\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(x=9 \cos \theta, y=6 \sin \theta\)

Step-by-step Solution

Detailed explanation

\(x = \frac{3a+2(0)}{5} = \frac{3a}{5}, y = \frac{3(0)+2b}{5} = \frac{2b}{5}\) \(a=\frac{5x}{3}, b=\frac{5y}{2}\) \(a^2+b^2 = 15^2\) \(\left(\frac{5x}{3}\right)^2 + \left(\frac{5y}{2}\right)^2 = 225\) \(\frac{25x^2}{9} + \frac{25y^2}{4} = 225\)…