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TS EAMCET · Maths · Limits

limx3-x3-3x2-4x+122x3-7x2+2x+3=

  1. A 0
  2. B
  3. C 514
  4. D 613
Verified Solution

Answer & Solution

Correct Answer

(C) 514

Step-by-step Solution

Detailed explanation

Given, L=limx→3-x3-3x2-4x+122x3-7x2+2x+3 Checking the form we get, L=00 form at  x=3 So, applying L-hospital rule in limit we get, L=limx→3-3x2-6x-46x2-14x+2 L=3×32-6×3-46×32-14×3+2=514