TS EAMCET · Maths · Permutation Combination
If \(n\) is an integer with \(0 \leq n \leq 11\), then the minimum value of \(n !(11-1)\) ! is attained when a value of \(n\) equals to
- A \(11\)
- B \(5\)
- C \(7\)
- D \(9\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
We know, \({ }^{11} C_n\) is maximum when \(n=5\). \[ \therefore{ }^{11} C_n=\frac{11 !}{n !(11-n) !} \] \(\therefore n !(11-n) !\) is minimum when \(n=5\).
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