TS EAMCET · Maths · Probability
In a certain recruitment test with multiple choice questions, there are four options to each question, out of which only one is correct. An intelligent student knows \(90 \%\) of the correct answers while a weals student knows only \(20 \%\) of the correct answers. If a weals student gets the correct answer, the probability that he was guessing is
- A 0.03
- B 0.27
- C 0.4
- D 0.5
Answer & Solution
Correct Answer
(D) 0.5
Step-by-step Solution
Detailed explanation
Let \(E_1\) be the event that a weak student know the answer and \(B_2\) be the event that a weak student guess the answer and \(A\) be the event that a weak student gets the correct answer. Then, required probability \(=P\left(\frac{B_2}{A}\right)\) Clearly,…
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