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TS EAMCET · Physics · Motion In One Dimension

A ball thrown upwards vertically reaches a height \(25 \mathrm{~m}\) in \(1 \mathrm{~s}\). The ratio of total distance covered by the ball in time \(t=2 \mathrm{~s}\) and \(t=4 \mathrm{~s}\) is (Use, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )

  1. A 1
  2. B \(\frac{4}{5}\)
  3. C \(\frac{2}{3}\)
  4. D \(\frac{3}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{4}{5}\)

Step-by-step Solution

Detailed explanation

Given that, the height achieved in \(1 \mathrm{~s}, h=25 \mathrm{~m}\) Let \(u\) be the initial velocity in upward direction. By equation of motion, \( h=u t-\frac{1}{2} g t^2 \)…
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