TS EAMCET · Maths · Complex Number
If \(i=\sqrt{-1}\) then \(\sum_{n=0}^{\infty}\left(\frac{i}{3}\right)^n=\)
- A \(\frac{9-3 i}{10}\)
- B \(9-3 i\)
- C \(9+3 i\)
- D \(\frac{9+3 \mathrm{i}}{10}\)
Answer & Solution
Correct Answer
(D) \(\frac{9+3 \mathrm{i}}{10}\)
Step-by-step Solution
Detailed explanation
\(\left(\frac{i}{3}\right)^0+\left(\frac{i}{3}\right)^1+\left(\frac{i}{3}\right)^2+\ldots \infty\)…
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