TS EAMCET · Maths · Permutation Combination
15 lines are concurrent at a point P. A line L not passing through \(\mathrm{P}\) intersects all the 15 lines and forms triangles with them. Then the number of triangles having \(\mathrm{L}\) as one of its side is
- A 310
- B 91
- C 182
- D 105
Answer & Solution
Correct Answer
(D) 105
Step-by-step Solution
Detailed explanation
Here no. of triangls are \({ }^{15} \mathrm{C}_2=105\)
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