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TS EAMCET · Maths · Differentiation

If fx=logee2x3x+55-3x23, x-53,53, then the value of dfdx at x=1, is

  1. A 54
  2. B 74
  3. C 114
  4. D 134
Verified Solution

Answer & Solution

Correct Answer

(D) 134

Step-by-step Solution

Detailed explanation

Given, fx=logee2x3x+55-3x23 ⇒fx=logee2x+loge3x+55-3x23 ⇒fx=2x+23loge3x+55-3x ⇒fx=2x+23loge3x+5-loge5-3x Now differentiating the function with respect to x we get, dfdx=2+2313x+5×3-15-3x×-3 ⇒dfdx=2+213x+5+15-3x…