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TS EAMCET · Maths · Functions

Let \(f:[0,10] \rightarrow[1,20]\) be a function defined as \(f(x)=\left\{\begin{array}{ll}\frac{60-5 x}{3}, & 0 \leq x \leq 6 \ 10, & 6 \leq x \leq 7 \ 31-3 x, & 7 \leq x \leq 10\end{array}\right.\) then \(f\) is

  1. A bijective function
  2. B one-one but not onto function
  3. C onto but not one-one function
  4. D neither one-one nor onto function
Verified Solution

Answer & Solution

Correct Answer

(C) onto but not one-one function

Step-by-step Solution

Detailed explanation

We have, \(f(x)= \begin{cases}\frac{60-5 x}{3}, & 0 \leq x \leq 6 \\ 10, & 6 \leq x \leq 7 \\ 31-3 x, & 7 \leq x \leq 10\end{cases}\) Now, \(f(x)=10 \forall x \in[6,7]\) So, \(f(x)\) is not one-one. Again,…