TS EAMCET · Maths · Circle
If tangents are drawn to the circle \(x^2+y^2=12\) at the points of intersection with the circle \(x^2+y^2-5 x+3 y-2=0\), then the ordinate of the point of intersection of these tangents is
- A \(-\frac{18}{5}\)
- B \(-\frac{12}{5}\)
- C \(-\frac{9}{5}\)
- D \(-\frac{3}{5}\)
Answer & Solution
Correct Answer
(A) \(-\frac{18}{5}\)
Step-by-step Solution
Detailed explanation
Let \((h, k)\) be the point of intersection of tangents then the chord of contact of tangents is the common chord of the circle \(x^2+y^2=12\) and \[ \begin{aligned} x^2+y^2-5 x+3 y-2 & =0 \\ 5 x-3 y-10 & =0 \end{aligned} \] i.e. \[ 5 x-3 y-10=0 \] Also, the equation of the…
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