TS EAMCET · Maths · Three Dimensional Geometry
If the plane passing through the points \(\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}, 2 \hat{\mathbf{i}}-\hat{\mathbf{k}}\) and the origin meets the line passing through the points \(\hat{\mathbf{i}}+3 \hat{\mathbf{j}}-2 \hat{\mathbf{k}}\) and \(\hat{\mathbf{i}}-\hat{\mathbf{j}}+3 \hat{\mathbf{k}}\) at the points \(A\), then \(A=\)
- A \(\frac{1}{9}(9 \hat{\mathbf{i}}+8 \hat{\mathbf{j}}+7 \hat{\mathbf{k}})\)
- B \(\frac{1}{11}(11 \hat{\mathbf{i}}+9 \hat{\mathbf{j}}+8 \hat{\mathbf{k}})\)
- C \(\frac{1}{11}(11 \hat{\mathbf{i}}-9 \hat{\mathbf{j}}+8 \hat{\mathbf{k}})\)
- D \(\frac{1}{11}(-11 \hat{\mathbf{i}}+9 \hat{\mathbf{j}}-8 \hat{\mathbf{k}})\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{11}(11 \hat{\mathbf{i}}+9 \hat{\mathbf{j}}+8 \hat{\mathbf{k}})\)
Step-by-step Solution
Detailed explanation
Equation of plane passing through points \((\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}),(2 \hat{\mathbf{i}}-\hat{\mathbf{k}})\) and origin is…
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