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TS EAMCET · Maths · Indefinite Integration

If \(\int e^{\alpha x}\left(\frac{1-\beta \sin x}{1-\cos x}\right) d x=-e^x \cot \frac{x}{2}+c\), then \(\frac{\alpha^2+\beta^2}{2 \alpha \beta}=\)

  1. A -1
  2. B 1
  3. C 2
  4. D -2
Verified Solution

Answer & Solution

Correct Answer

(B) 1

Step-by-step Solution

Detailed explanation

We have, \[ \int e^{\alpha x}\left(\frac{1-\beta \sin x}{1-\cos x}\right) d x=-e^x \cot \frac{x}{2}+c \] On differentiating by both sides, we get…