TS EAMCET · Maths · Indefinite Integration
If \(\int e^{\alpha x}\left(\frac{1-\beta \sin x}{1-\cos x}\right) d x=-e^x \cot \frac{x}{2}+c\), then \(\frac{\alpha^2+\beta^2}{2 \alpha \beta}=\)
- A -1
- B 1
- C 2
- D -2
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
We have, \[ \int e^{\alpha x}\left(\frac{1-\beta \sin x}{1-\cos x}\right) d x=-e^x \cot \frac{x}{2}+c \] On differentiating by both sides, we get…
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