TS EAMCET · Maths · Circle
Let \(A\) be the centre of the circle \(x^2+y^2-2 x-4 y-20=0\). If the tangents drawn at the point \(B(1,7)\) and \(D(4,-2)\) on the given circle meet at the point \(C\), then the area of the quadrilateral \(A B C D\) is
- A 60
- B 65
- C 70
- D 75
Answer & Solution
Correct Answer
(D) 75
Step-by-step Solution
Detailed explanation
Equation of circle \[ x^2+y^2-2 x-4 y-20=0 \] Centre of circle \((1,2)\), radius \(=5\) Equation of tangents at \((1,7)\) is…
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