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TS EAMCET · Maths · Permutation Combination

9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of arranging one ball in each of the boxes is

  1. A \(18720\)
  2. B \(18270\)
  3. C \(17280\)
  4. D \(12780\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(17280\)

Step-by-step Solution

Detailed explanation

Required number of arrangements \[ \begin{aligned} & ={ }^6 P_5 \times 4 ! \\ & =720 \times 24 \\ & =17280 \end{aligned} \]