TS EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta, \gamma\) are the roots of the equation \(x^3-\mathrm{Px}^2+\mathrm{Q} x-\mathrm{R}=0\) and \((\alpha-2)^2,(\beta-2)^2\), \((\gamma-2)^2\) are the roots of the equation \(x^3-5 x^2+4 x=0\), then the possible least value of \(\mathrm{P}+\mathrm{Q}+\mathrm{R}\) is
- A \(5\)
- B \(-7\)
- C \(-1\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
\(x^3-5x^2+4x=0 \Rightarrow x(x-1)(x-4)=0\) The roots \((\alpha-2)^2, (\beta-2)^2, (\gamma-2)^2\) are \(\{0, 1, 4\}\). Thus, \(\{\alpha-2, \beta-2, \gamma-2\}\) can be \(\{0, \pm1, \pm2\}\) with distinct squares. The possible sets are…
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