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TS EAMCET · Maths · Complex Number

If \(\alpha, \beta\) are the roots of the equation \(x^2-2 x+2=0\) then \(\alpha^{2020}+\beta^{2020}=\)

  1. A \(2^{1011}\)
  2. B \(-2^{1011}\)
  3. C \(2^{2021}\)
  4. D \(2^{-2021}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-2^{1011}\)

Step-by-step Solution

Detailed explanation

Given equation is \(x^2-2 x+2=0\) \[ \begin{aligned} & \therefore \alpha+\beta=2 \text { and } \alpha \cdot \beta=2 \\ & \because(\alpha-\beta)^2=(\alpha+\beta)^2-4 \alpha \beta=4-8=-4 \\ & \alpha-\beta= \pm 2 i \\ & \alpha+\beta=2 \end{aligned} \] On solving equations (i) and…