TS EAMCET · Maths · Circle
\(x-2 y-6=0\) is a normal to the circle \(x^2+y^2+2 g x+2 f y-8=0\). If the line \(y=2\) touches this circle, then the radius of the circle can be
- A \(\sqrt{32}\)
- B \(6\)
- C \(4\)
- D \(\sqrt{18}\)
Answer & Solution
Correct Answer
(C) \(4\)
Step-by-step Solution
Detailed explanation
Centre of circle is \((-g,-f)\) It lies on the normal, \(-\mathrm{g}+2 f-6=0\)…
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