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TS EAMCET · Maths · Permutation Combination

If \(x\) and \(y\) represent the number of arrangements of the letters of word ATRAPATRAM such that (i) all A's are together and (ii) no two A's are together respectively, then \(x+y\)

  1. A \(\frac{10 !}{4 ! 2 ! 2 !}\)
  2. B \(\frac{7 ! \times 15}{2 ! 2 ! 4 !}\)
  3. C \(\frac{6 !}{2 ! 2 !} \times 42\)
  4. D \(\frac{7 !}{2 ! 2 !}+\frac{6 ! \cdot 7 p_4}{2 ! 2 !}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{6 !}{2 ! 2 !} \times 42\)

Step-by-step Solution

Detailed explanation

Given, word ATRAPATRAM Here, \(\mathrm{A} \rightarrow 4\) times \(\mathrm{T} \rightarrow 2\) times \(\mathrm{R} \rightarrow 2\) times \(\mathrm{P} \rightarrow 1\) time \(M \rightarrow 1\) time (i) All A's are together, Then it will be consider as one letter and remaining 6…