TS EAMCET · Maths · Matrices
\(\mathrm{A}, \mathrm{C}\) are \(3 \times 3\) matrices. \(\mathrm{B}, \mathrm{D}\) are \(3 \times 1\) matrices. If \(\mathrm{AX}=\mathrm{B}\) has unique solution and \(\mathrm{CX}=\mathrm{D}\) has infinite number of solutions, then
- A \(\operatorname{rank}\) of \([\mathrm{A}: \mathrm{D}]=\operatorname{rank}\) of \([\mathrm{C}: \mathrm{B}]\)
- B \(\operatorname{rank}\) of \(\mathrm{A}=\operatorname{rank}\) of C
- C \(\operatorname{rank}\) of \([\mathrm{A}: \mathrm{B}] < \operatorname{rank}\) of \([\mathrm{B}: \mathrm{D}]\)
- D \(\operatorname{rank}\) of \([\mathrm{A}: \mathrm{D}] \geq \operatorname{rank}\) of \([\mathrm{C}: \mathrm{B}]\)
Answer & Solution
Correct Answer
(D) \(\operatorname{rank}\) of \([\mathrm{A}: \mathrm{D}] \geq \operatorname{rank}\) of \([\mathrm{C}: \mathrm{B}]\)
Step-by-step Solution
Detailed explanation
For \( \mathrm{AX}=\mathrm{B} \) to have a unique solution with \( \mathrm{A} \) being \( 3 \times 3 \): \( \operatorname{rank}(\mathrm{A}) = \operatorname{rank}([\mathrm{A}: \mathrm{B}]) = 3 \) For \( \mathrm{CX}=\mathrm{D} \) to have infinite solutions with \( \mathrm{C} \)…
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