TS EAMCET · Maths · Vector Algebra
If \(\bar{a}=(x+2 y-3) \bar{i}+(2 x-y+3) \bar{j}\) and \(\bar{b}=(3 x-2 y) \bar{i}+(x-y+1) \bar{j}\) are two vectors such that \(\bar{a}=2 \bar{b}\), then \(y-5 x=\)
- A \(10\)
- B \(-10\)
- C \(8\)
- D \(-8\)
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
From \(\bar{a}=2\bar{b}\), equate the j-components: \(2x-y+3 = 2(x-y+1)\) \(2x-y+3 = 2x-2y+2\) \(y = -1\) Equate the i-components: \(x+2y-3 = 2(3x-2y)\) \(x+2(-1)-3 = 2(3x-2(-1))\) \(x-5 = 2(3x+2)\) \(x-5 = 6x+4\) \(-9 = 5x\) \(x = -\frac{9}{5}\) Calculate \(y-5x\):…
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