TS EAMCET · Maths · Indefinite Integration
If \(\frac{1}{x^4+x^2+1}=\frac{A x+B}{x^2+a x+1}+\frac{C x+D}{x^2-a x+1}\) then \(A+B-C+D=\)
- A \(a\)
- B \(2 a\)
- C \(3 a\)
- D \(4 a\)
Answer & Solution
Correct Answer
(B) \(2 a\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{x^4+x^2+1}=\frac{A x+B}{x^2+a x+1}+\frac{C x+D}{x^2-a x+1}\)…
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