TS EAMCET · Maths · Straight Lines
If a straight line perpendicular to \(2 x-3 y+7=0\) forms a triangle with the co-ordinate axes whose area is 3 sq. units, then the equation of the straight line is :
- A \(3 x+2 y= \pm 2\)
- B \(3 x+2 y= \pm 6\)
- C \(3 x+2 y= \pm 4\)
- D \(3 x+2 y= \pm 8\)
Answer & Solution
Correct Answer
(B) \(3 x+2 y= \pm 6\)
Step-by-step Solution
Detailed explanation
The given line is \(2 x-3 y+7=0\) A perpendicular line to given line is \[ 3 x+2 y+k=0 \] Put \(y=0 \Rightarrow 3 x+k=0\) \[ x=-\frac{k}{3} \] Put \(x=0 \Rightarrow 0+2 y+k=0\) \[ y=-\frac{k}{2} \] Area of the triangle \(O A B=\frac{1}{2} \cdot O A \cdot O B\)…
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