TS EAMCET · Physics · Mechanical Properties of Fluids
Tanks \(A\) and \(B\) open at the top contain two different liquids upto certain height in them. A hole is made to the wall of each tank at a depth \(h\) from the surface of the liquid. The area of the hole in \(B\) is twice that of in \(A\). If the liquid mass flux through each hole is equal, then the ratio of the densities of the liquids respectively, is
- A \(1\)
- B \(\frac{3}{2}\)
- C \(\frac{2}{3}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
Let the velocity of liquid from hole in \(A\) is \(v_1\) and velocity of liquid from hole in \(B\) is \(v_2\), then from equation of continuity \[ \begin{aligned} A_1 v_1 & =A_2 v_2 \\ A v_1 & =2 A v_2 \\ v_2 & =\frac{v_1}{2} \end{aligned} \] Volume of liquid coming out per…
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