TS EAMCET · Maths · Quadratic Equation
If \((x-2)\) is a common factor of the expressions \(\mathrm{x}^2+\mathrm{ax}+\mathrm{b}\) and \(\mathrm{x}^2+\mathrm{cx}+\mathrm{d}\), then \(\frac{b-d}{c-a}=\)
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(x^2+a x+b\) have \((x-2)\) as factor \(\begin{array}{r} \therefore \quad(2)^2+2 a+b=0 \\ 2 a+b=4 ...(i) \end{array}\) Similarly, \(x^2+c x+d=0\) \(\begin{aligned} & \Rightarrow(2)^2+2 c+d=0 \\ & \Rightarrow 2 c+d=-4... (ii) \end{aligned}\) (i) - (ii)…
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