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TS EAMCET · Maths · Complex Number

If ω is a complex cube root of unity, then 1-ω+ω26+1-ω2+ω6=

  1. A 0
  2. B 6
  3. C 64
  4. D 128
Verified Solution

Answer & Solution

Correct Answer

(D) 128

Step-by-step Solution

Detailed explanation

Given that 1-ω+ω26+1-ω2+ω6 We know that 1+ω+ω2=0 & ω3=1 =-2ω6+-2ω26 =64ω6+64ω12 we know that ω3n=1. Required value=64+64=128.
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