TS EAMCET · Maths · Pair of Lines
If \(2 x^2+x y-6 y^2+\mathrm{k}=0\) is the transformed equation of \(2 x^2+x y-6 y^2-13 x+9 y+15=0\) when the origin is shifted to the point \((a, b)\) by translation of axes, then \(\mathrm{k}=\)
- A \(1\)
- B \(0\)
- C \(21\)
- D \(15\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
\(4a + b - 13 = 0\) \(a - 12b + 9 = 0\) \(a = 3, b = 1\) \(\mathrm{k} = 2(3)^2 + (3)(1) - 6(1)^2 - 13(3) + 9(1) + 15\) \(\mathrm{k} = 18 + 3 - 6 - 39 + 9 + 15\) \(\mathrm{k} = 0\)
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