TS EAMCET · Maths · Straight Lines
The equation of a straight line, perpendicular to \(3 x-4 y=6\) and forming a triangle of area 6 sq. units with coordinate axes, is
- A \(x-2 y=6\)
- B \(4 x+3 y=12\)
- C \(4 x+3 y+24=0\)
- D \(3 x+4 y=12\)
Answer & Solution
Correct Answer
(B) \(4 x+3 y=12\)
Step-by-step Solution
Detailed explanation
Given equation of line is \[ 3 x-4 y=6 \] Perpendicular to above line is \[ 4 x+3 y=k \] \(\therefore\) Area of \(\triangle O A B\) \[ =\frac{1}{2} \times O A \times O B \]…
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