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TS EAMCET · Maths · Complex Number

If \(\alpha, \beta\) are the roots of the equation \(x^2-2 \sqrt{3} x+4=0\) then \(\alpha^6+\beta^6=\)

  1. A 128
  2. B -64
  3. C 64
  4. D -128
Verified Solution

Answer & Solution

Correct Answer

(D) -128

Step-by-step Solution

Detailed explanation

Given equation \(x^2-2 \sqrt{3} x+4=0\) with \(\alpha \& \beta\) roots of the equation. \(\begin{aligned} & \alpha+\beta=\frac{-b}{a}=2 \sqrt{3} \\ & \alpha \beta=\frac{c}{a}=4 \end{aligned}\) Now, \(\left(\alpha^6+\beta^6\right)=\left(\alpha^2\right)^3+\left(\beta^2\right)^3\)…
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