TS EAMCET · Maths · Three Dimensional Geometry
Equation of the plane through the mid-point of the line segment joining the points \(\mathrm{A}(4,5,-10)\) and \(\mathrm{B}(-1,2,1)\) and perpendicular to \(\mathrm{AB}\) is
- A \(10 x+6 y-22 z+135=0\)
- B \(10 x+6 y-22 z-135=0\)
- C \(5 x+3 y+11 z=135\)
- D \(10 x+6 y-22 z+185=0\)
Answer & Solution
Correct Answer
(B) \(10 x+6 y-22 z-135=0\)
Step-by-step Solution
Detailed explanation
D.R. of \(A B=(-1-4,2-5,1+10)=(-5,-3,11)\) Also mid point of \(A B \equiv\left(\frac{4-1}{2}, \frac{5+2}{2}, \frac{-10+1}{2}\right)\) \(P \equiv\left(\frac{3}{2}, \frac{7}{2}, \frac{-9}{2}\right)\) \(\therefore \quad\) Equation of plane passing through \(P\) and having D.R. of…
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