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TS EAMCET · Maths · Quadratic Equation

If a polynomial \(\mathrm{P}(x)\) given by \(P(x)=2 x^4+a x^3+b x^2+c x+d\) is such that \(\mathrm{P}(1)=4, \mathrm{P}(2)=7, \mathrm{P}(3)=12\) and \(\mathrm{P}(4)=19\), then \(\mathrm{P}(5)=\)

  1. A 28
  2. B 76
  3. C 26
  4. D 72
Verified Solution

Answer & Solution

Correct Answer

(B) 76

Step-by-step Solution

Detailed explanation

\(\mathrm{P}(x)=2 x^4+a x^3+b x^2+c x+d\) \(\begin{aligned} & \mathrm{P}(1)=4=1^2+3 \\ & \mathrm{P}(2)=7=2^2+3 \\ & \mathrm{P}(3)=12=3^2+3 \\ & \mathrm{P}(4)=19=4^2+3 \\ & \therefore \mathrm{P}(x)=x^2+3\end{aligned}\) But to make it degree 4 polynomial with leading coefficient…
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