ExamBro
ExamBro
TS EAMCET · Maths · Sequences and Series

\(\frac{1}{1 \cdot 3}+\frac{1}{2 \cdot 5}+\frac{1}{3 \cdot 7}+\frac{1}{4 \cdot 9}+\ldots\) is equal to

  1. A \(2 \log _e 2-2\)
  2. B \(2-\log _e 2\)
  3. C \(2 \log _e 4\)
  4. D \(\log _e 4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2-\log _e 2\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { Let } \quad S=\frac{1}{1 \cdot 3}+\frac{1}{2 \cdot 5}+\frac{1}{3 \cdot 7}+\frac{1}{4 \cdot 9}+\ldots \\ & \therefore \quad T_n=\frac{1}{n(2 n+1)} \\ & =\frac{1}{n}-\frac{2}{(2 n+1)} \\ & \Rightarrow \quad S=\sum_{n=1}^{\infty}…