TS EAMCET · Chemistry · Solutions
At \(300 \mathrm{~K}, 0.06 \mathrm{~kg}\) of an organic solute is dissolved in 1 kg water. The vapour pressure of solution at 300 K is 3.768 kPa . If vapour pressure of water at that temperature is 3.78 kPa , what is the molar mass of the organic solute (in \(\mathrm{g} \mathrm{mol}^{-1}\) )? (Assume the solution in dilute)
- A 180
- B 120
- C 340
- D 260
Answer & Solution
Correct Answer
(C) 340
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {} \frac{\Delta \mathrm{P}}{\mathrm{P}^0}=\frac{\mathrm{W}_2 \times \mathrm{M}_1}{\mathrm{M}_2 \times \mathrm{W}_1} \\ & \mathrm{M}_2=\frac{\mathrm{W}_2 \times \mathrm{M}_1 \times \mathrm{P}^0}{\Delta \mathrm{P} \times \mathrm{W}_1} \\ & =\frac{60 \times…
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