TS EAMCET · Maths · Functions
Given that for any \(n \in \mathbf{N}\) there exist an odd integer \(q\) and a non-negative integer \(r\) such that, \(n\) can be written uniquely as \(n=q \times 2^r\). Let \(f: \mathbf{N} \rightarrow \mathbf{N} \times \mathbf{N}\) be function defined by \(f(n)=\left(r+1, \frac{q+1}{2}\right)\). Then,
- A \(f\) is one-one but not onto
- B \(f\) is onto but not one-one
- C \(f\) is a bijection
- D only \(f^{-1}(1,1)\) does not exist because \(f\) is not a bijection
Answer & Solution
Correct Answer
(C) \(f\) is a bijection
Step-by-step Solution
Detailed explanation
We have, \(f(n)=\left(r+1, \frac{q+1}{2}\right)\) For one-one…
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