TS EAMCET · Chemistry · p Block Elements (Group 13 & 14)

The correct order of reducing ability of the following hydrides is

A ${BiH}_{3} > {SbH}_{3} > {PH}_{3} > {NH}_{3}$
B ${NH}_{3} > {PH}_{3} > {SbH}_{3} > {BiH}_{3}$
C ${SbH}_{3} > {BiH}_{3} > {PH}_{3} > {NH}_{3}$
D ${PH}_{3} > {BiH}_{3} > {SbH}_{3} > {NH}_{3}$

Verified Solution

Answer & Solution

Correct Answer

(A) ${BiH}_{3} > {SbH}_{3} > {PH}_{3} > {NH}_{3}$

Step-by-step Solution

Detailed explanation

The reducing character of the hydrides of group V elements depends upon the stability of hydrides. With progressive decrease in stability, the reducing character of hydrides increases as we move down the group. Thus, ammonia, being stable, has least reducing ability. The order…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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