TS EAMCET · Maths · Application of Derivatives
The equation of the tangent to the curve at is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(B)
Step-by-step Solution
Detailed explanation
xy5+2x2y-x3+y+1=0 .....i Put x=0 0+0-0+y+1=0 ⇒y=-1 Differentiating curve w.r.t. x y5+5xy4dydx+2x2dydx+4xy-3x2+dydx=0 ⇒dydx0,-1=1 Tangent ≡y--1=1x-0 ⇒y=x-1
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