TS EAMCET · Maths · Ellipse
For the ellipse given by \(\frac{(x-3)^2}{25}+\frac{(y-2)^2}{16}=1\), match the equations of the lines given in List I with those on the List II.
- A (a)
- B (b)
- C (c)
- D (d)
Answer & Solution
Correct Answer
(D) (d)
Step-by-step Solution
Detailed explanation
Given equation of ellipse \[ \frac{(x-3)^2}{25}+\frac{(y-2)^2}{16}=1 \] Let \((x-3)=X\) and \((y-2)=Y\), then \[ \frac{x^2}{5^2}+\frac{y^2}{4^2}=1 \] Here, \(\quad a=5\) and \(b=4\). Also, \(\quad e=\sqrt{1-\frac{b^2}{a^2}}=\sqrt{1-\frac{16}{25}}=\frac{3}{5}\) Now, equation of…
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