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TS EAMCET · Maths · Limits

\(\lim _{x \rightarrow-2^{+}}\left([x]^2-[x]-2\right)+\lim _{x \rightarrow-3^{-}}\left([x]^2-4[x]+3\right)=\)

  1. A \(39\)
  2. B \(33\)
  3. C \(28\)
  4. D \(44\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(39\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text \quad \lim _{x \rightarrow-2^{+}}\left([-x]^2-[x]-2\right)+\lim _{x \rightarrow-3^{-}}\left([x]^2-4[x]+3\right) \\ & \because \quad \lim _{x \rightarrow-2^{+}}[x]=\lim _{h \rightarrow 0}[-2+h]=-2 \\ & \quad \lim _{x \rightarrow-3^{-}}[x]=\lim _{h…

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