TS EAMCET · Maths · Vector Algebra
For scalars \(\lambda, \mu\) if the vector equation of a plane is \(\mathbf{r}=(2+3 \lambda-\mu) \hat{\mathbf{i}}+(1-2 \lambda+3 \mu) \hat{\mathbf{j}}+(-2+2 \lambda+\mu) \hat{\mathbf{k}}\), then its Cartesian equation is
- A \(8 x-5 y-7 z+35=0\)
- B \(8 x-5 y+7 z-35=0\)
- C \(8 x+5 y-7 z+35=0\)
- D \(8 x+5 y-7 z-35=0\)
Answer & Solution
Correct Answer
(D) \(8 x+5 y-7 z-35=0\)
Step-by-step Solution
Detailed explanation
Given, vector equation of plane \(\mathbf{r}=(2+3 \lambda-\mu) \hat{\mathbf{i}}+(1-2 \lambda+3 \mu) \hat{\mathbf{j}}+(-2+2 \lambda+\mu) k\) \(\ldots\) (i) Let \(\mathbf{r}=x \hat{\mathbf{i}}+y \hat{\mathbf{j}}+z \hat{\mathbf{k}}\) \(\ldots\) (ii) \(\therefore\) Compare Eqs. (i)…
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