TS EAMCET · Maths · Vector Algebra
If \(|\mathbf{a}|=4,|\mathbf{b}|=5,|\mathbf{a}-\mathbf{b}|=3\) and \(\theta\) is the angle between the vectors \(\mathbf{a}\) and \(\mathbf{b}\), then \(\tan ^2 \theta=\)
- A \(\frac{4}{3}\)
- B \(\frac{3}{4}\)
- C \(\frac{16}{9}\)
- D \(\frac{9}{16}\)
Answer & Solution
Correct Answer
(D) \(\frac{9}{16}\)
Step-by-step Solution
Detailed explanation
Given that, \(|\mathbf{a}|=4,|\mathbf{b}|=5,|\mathbf{a}-\mathbf{b}|=3\) Now, \(|\mathbf{a}-\mathbf{b}|^2=|\mathbf{a}|^2+|\mathbf{b}|^2-2 \mathbf{a} \cdot \mathbf{b}\)…
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