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TS EAMCET · Maths · Ellipse

Assertion (A): The image of \(\frac{x^2}{25}+\frac{y^2}{16}=1\) in the line \(x+y=10\) is \[ \frac{(x-10)^2}{16}+\frac{(y-10)^2}{25}=1 \text {. } \] Reason (R): The image of a curve ' \(\mathrm{C}\) ' in a line \(\mathrm{L}\) is the locus of the image of every point of \(\mathrm{C}\) with respect to the line \(\mathrm{L}\). The correct option among the following is:

  1. A (A) is true, (R) is true and (R) is the correct explanation for (A)
  2. B (A) is true, (R) is true but (R) is not the correct explanation for (A)
  3. C (A) is true but (R) is false
  4. D (A) is false but (R) is true
Verified Solution

Answer & Solution

Correct Answer

(A) (A) is true, (R) is true and (R) is the correct explanation for (A)

Step-by-step Solution

Detailed explanation

Given equation of ellipse is \(\frac{x^2}{25}+\frac{y^2}{16}=1\) The image of the ellipse in the line \(x+y-10\) will be \(\frac{(x-h)^2}{16}+\frac{(y-k)^2}{25}=1\) Centre of original equation is \((0,0)\) and other equation is \((h, k)\) Midpoint is…
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