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TS EAMCET · Maths · Differentiation

Let \(f(x)=\sin x, g(x)=\cos x, h(x)=x^2\) then \(\lim _{x \rightarrow 1} \frac{f(g(h(x)))-f(g(h(1)))}{x-1}=\)

  1. A 0
  2. B \(-2 \sin 1 \cos (\cos 1)\)
  3. C \(\infty\)
  4. D \(-2 \sin 1 \cos 1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-2 \sin 1 \cos (\cos 1)\)

Step-by-step Solution

Detailed explanation

Given \(f(x)=\sin x, g(x)=\cos x, h(x)=x^2\) \[ \lim _{x \rightarrow 1} \frac{f(g(h(x)))-f(g(h(1)))}{x-1}=\lim _{x \rightarrow 1} \frac{\sin \left(\cos x^2\right)-\sin (\cos 1)}{x-1} \] If Apply limit it gives \(\frac{0}{0}\) form, then apply L'Hospital rule.…