TS EAMCET · Maths · Vector Algebra
\(\mathbf{a}=\mathbf{i}+\mathbf{j}-2 \mathbf{k} \Rightarrow \sum\{(\mathbf{a} \times \mathbf{i}) \times \mathbf{j}\}^2\) is equal to
- A \(\sqrt{6}\)
- B \(6\)
- C \(36\)
- D \(6 \sqrt{6}\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
Given, \(\mathbf{a}=\mathbf{i}+\mathbf{j}-2 \mathbf{k}\)…
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