TS EAMCET · Maths · Area Under Curves
Area of the region enclosed between the curves \(y^2=4(x+7)\) and \(y^2=5(2-x)\) is
- A \(\frac{32 \sqrt{2}}{3}\)
- B \(\frac{8}{3}\)
- C \(\frac{1}{6}\)
- D \(24 \sqrt{5}\)
Answer & Solution
Correct Answer
(D) \(24 \sqrt{5}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & 4 x+28=10-5 x \Rightarrow 9 x=-18 \Rightarrow x=-2 \\ & y^2=20 \Rightarrow y=\sqrt{20} \end{aligned}\) Point of intersection is \((-2, \sqrt{20})\) and \((-2,-\sqrt{20})\) Upper curve \(\left(2-\frac{y^2}{5}\right) ;\) Lower curve…
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