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TS EAMCET · Maths · Limits

If fx=-sin2x+cos5x, then limx01xf'x

  1. A exist and is equal to 0
  2. B exist and is equal to 7
  3. C exist and is equal to 3
  4. D does not exist
Verified Solution

Answer & Solution

Correct Answer

(C) exist and is equal to 3

Step-by-step Solution

Detailed explanation

If fx=-sin2x+cos5x...................i To find:limx→01xf'x Differentiating equation i with respect to x, we get f'x=-2sinx.cosx+5cos4x.-sinx f'x=-sinx2.cosx-5cos4x Now, limx→01xf'x =limx→01x×-sinx2cosx-5cos4x…