TS EAMCET · Maths · Limits
\(\lim _{x \rightarrow 0}\left(\frac{\sinh 2 x}{2 x}\right)^{\frac{1}{x^2}}=\)
- A 0
- B \(e^{\frac{1}{3}}\)
- C \(e^{\frac{2}{3}}\)
- D \(e^{\frac{4}{3}}\)
Answer & Solution
Correct Answer
(C) \(e^{\frac{2}{3}}\)
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