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TS EAMCET · Maths · Three Dimensional Geometry

Let 3i^+j^-k^ be the position vector of a point B. Let A be a point on the line which is passing through B and parallel to the vector 2i^-j^+k^. If BA=18, then the position vector of A is

  1. A -9i^+7j^-13k^
  2. B -9i^+3j^+12k^
  3. C 9i^-3j^+2k^
  4. D 3i^-j^+7k^
Verified Solution

Answer & Solution

Correct Answer

(A) -9i^+7j^-13k^

Step-by-step Solution

Detailed explanation

Vector equation of the given line is, r=3i^+j^-k^+t2i^-j^+2k^ ⇒BA→=t2i^-j^+2k^=2i^t-j^t+2k^t ⇒18=4t2+t2+4t2=±3t ∴ t=±6 ∴ OA→=3i^+j^-k^±62i^-j^+2k^ =3i^+12i^+j^-6j^-k^+12k^ =15i^-5j^+11k^ or =3i^-12i^+j^+6j^-k^-12k^…