TS EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C, a^4+b^4+c^4=2 b^2 c^2+2 a^2 b^2\), then \(B=\)
- A \(\frac{\pi}{4}\) or \(\frac{3 \pi}{4}\)
- B \(\frac{\pi}{2}\)
- C \(\frac{\pi}{3}\) or \(\frac{2 \pi}{3}\)
- D \(\frac{\pi}{6}\) or \(\frac{5 \pi}{6}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{4}\) or \(\frac{3 \pi}{4}\)
Step-by-step Solution
Detailed explanation
We have, \(\quad a^4+b^4+c^4=2 b^2\left(c^2+a^2\right)\) \[ \Rightarrow a^4+b^4+c^4-2 b^2 c^2-2 a^2 b^2=0 \] Add \(2 a^2 c^2\) on both sides, we get…
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