TS EAMCET · Maths · Permutation Combination
A student is asked to answer 10 out of 13 questions in an examination such that he must answer atleast four questions from the first five questions. Then the total number of possible choices available to him is
- A \(186\)
- B \(176\)
- C \(286\)
- D \(196\)
Answer & Solution
Correct Answer
(D) \(196\)
Step-by-step Solution
Detailed explanation
\(\left({ }^5 \mathrm{C}_4 \times{ }^8 \mathrm{C}_6\right)+\left({ }^5 \mathrm{C}_5 \times{ }^8 \mathrm{C}_5\right)\) \(=(5 \times 28)+(1 \times 56)=196\)
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